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20122002113031 = 32713533131481041
BaseRepresentation
bin1001001001101000001001…
…10010011100001000000111
32122020122101220221222220200
410210310010302130020013
510114134330020104111
6110443530430501543
74144523653616340
oct444640462341007
978218356858820
1020122002113031
116458769682325
12230b9419648b3
13b2c65c205170
144d7ca544d0c7
1524d6459ba256
hex124d04c9c207

20122002113031 has 96 divisors (see below), whose sum is σ = 36563870109312. Its totient is φ = 10380265758720.

The previous prime is 20122002113021. The next prime is 20122002113033. The reversal of 20122002113031 is 13031120022102.

20122002113031 is a `hidden beast` number, since 201 + 220 + 0 + 211 + 3 + 0 + 31 = 666.

It is not a de Polignac number, because 20122002113031 - 25 = 20122002112999 is a prime.

It is a super-2 number, since 2×201220021130312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20122002112995 and 20122002113013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20122002113033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 12845871 + ... + 14326911.

It is an arithmetic number, because the mean of its divisors is an integer number (380873646972).

Almost surely, 220122002113031 is an apocalyptic number.

20122002113031 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

20122002113031 is a deficient number, since it is larger than the sum of its proper divisors (16441867996281).

20122002113031 is a wasteful number, since it uses less digits than its factorization.

20122002113031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1481433 (or 1481430 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 20122002113031 its reverse (13031120022102), we get a palindrome (33153122135133).

The spelling of 20122002113031 in words is "twenty trillion, one hundred twenty-two billion, two million, one hundred thirteen thousand, thirty-one".

Divisors: 1 3 7 9 13 21 39 53 63 91 117 159 273 313 371 477 689 819 939 1113 2067 2191 2817 3339 4069 4823 6201 6573 12207 14469 16589 19719 28483 36621 43407 49767 85449 116123 149301 215657 256347 348369 646971 1045107 1481041 1509599 1940913 4443123 4528797 10367287 13329369 13586391 19253533 31101861 57760599 78495173 93305583 134774731 173281797 235485519 404324193 463565833 549466211 706456557 1020437249 1212972579 1390697499 1648398633 3061311747 3244960831 4172092497 4945195899 6026355829 7143060743 9183935241 9734882493 18079067487 21429182229 24568989149 29204647479 42184490803 54237202461 64287546687 73706967447 126553472409 171982924043 221120902341 319396858937 379660417227 515948772129 958190576811 1547846316387 2235778012559 2874571730433 6707334037677 20122002113031