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20130121233222 = 2372111323531013889
BaseRepresentation
bin1001001001110111010001…
…01110011011001101000110
32122021102100202112000222220
410210323220232123031012
510114302442013430342
6110451352223433210
74145232112164600
oct444735056331506
978242322460886
1020130121233222
116461155710510
122311428a55806
13b303543248b0
144d8435884170
1524d96d6955ec
hex124ee8b9b346

20130121233222 has 768 divisors, whose sum is σ = 59090839234560. Its totient is φ = 4483454976000.

The previous prime is 20130121233221. The next prime is 20130121233371. The reversal of 20130121233222 is 22233212103102.

It is a junction number, because it is equal to n+sod(n) for n = 20130121233192 and 20130121233201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20130121233221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 5176167054 + ... + 5176170942.

It is an arithmetic number, because the mean of its divisors is an integer number (76941196920).

Almost surely, 220130121233222 is an apocalyptic number.

20130121233222 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 20130121233222, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (29545419617280).

20130121233222 is an abundant number, since it is smaller than the sum of its proper divisors (38960718001338).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20130121233222 is a wasteful number, since it uses less digits than its factorization.

20130121233222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4109 (or 4102 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 20130121233222 its reverse (22233212103102), we get a palindrome (42363333336324).

The spelling of 20130121233222 in words is "twenty trillion, one hundred thirty billion, one hundred twenty-one million, two hundred thirty-three thousand, two hundred twenty-two".