Base | Representation |
---|---|
bin | 1011101101111010001… |
… | …1010101010101110101 |
3 | 201020121002210101021112 |
4 | 2323132203111111311 |
5 | 11244231342100041 |
6 | 232251010524405 |
7 | 20354313214034 |
oct | 2733643252565 |
9 | 636532711245 |
10 | 201302300021 |
11 | 7840a99a509 |
12 | 3301b896705 |
13 | 15ca1080cc4 |
14 | 9a5904071b |
15 | 538296adeb |
hex | 2ede8d5575 |
201302300021 has 4 divisors (see below), whose sum is σ = 201325604844. Its totient is φ = 201278995200.
The previous prime is 201302299993. The next prime is 201302300029. The reversal of 201302300021 is 120003203102.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 49556992996 + 151745307025 = 222614^2 + 389545^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201302300021 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 201302299969 and 201302300005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201302300029) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11639450 + ... + 11656731.
It is an arithmetic number, because the mean of its divisors is an integer number (50331401211).
Almost surely, 2201302300021 is an apocalyptic number.
It is an amenable number.
201302300021 is a deficient number, since it is larger than the sum of its proper divisors (23304823).
201302300021 is an equidigital number, since it uses as much as digits as its factorization.
201302300021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23304822.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 201302300021 its reverse (120003203102), we get a palindrome (321305503123).
The spelling of 201302300021 in words is "two hundred one billion, three hundred two million, three hundred thousand, twenty-one".
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