Base | Representation |
---|---|
bin | 10010101111111101… |
… | …011111010101011000 |
3 | 1220222000220121201211 |
4 | 102233331133111120 |
5 | 312212243013422 |
6 | 13125402352504 |
7 | 1311614120536 |
oct | 225775372530 |
9 | 56860817654 |
10 | 20132001112 |
11 | 85a0a98453 |
12 | 3a9a1bb734 |
13 | 1b8ab441c2 |
14 | d8da47156 |
15 | 7cc642577 |
hex | 4aff5f558 |
20132001112 has 8 divisors (see below), whose sum is σ = 37747502100. Its totient is φ = 10066000552.
The previous prime is 20132001107. The next prime is 20132001119. The reversal of 20132001112 is 21110023102.
It is a tau number, because it is divible by the number of its divisors (8).
It is a junction number, because it is equal to n+sod(n) for n = 20132001092 and 20132001101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20132001119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1258250062 + ... + 1258250077.
Almost surely, 220132001112 is an apocalyptic number.
It is an amenable number.
20132001112 is a deficient number, since it is larger than the sum of its proper divisors (17615500988).
20132001112 is a wasteful number, since it uses less digits than its factorization.
20132001112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2516500145 (or 2516500141 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20132001112 its reverse (21110023102), we get a palindrome (41242024214).
The spelling of 20132001112 in words is "twenty billion, one hundred thirty-two million, one thousand, one hundred twelve".
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