Base | Representation |
---|---|
bin | 10010110000000101… |
… | …001100001110100000 |
3 | 1220222011201012010110 |
4 | 102300011030032200 |
5 | 312213302120000 |
6 | 13125513531320 |
7 | 1311640226523 |
oct | 226005141640 |
9 | 56864635113 |
10 | 20134020000 |
11 | 85a2147256 |
12 | 3a9aa13b40 |
13 | 1b8b3a0103 |
14 | d90010bba |
15 | 7cc8e0850 |
hex | 4b014c3a0 |
20134020000 has 120 divisors (see below), whose sum is σ = 66043809216. Its totient is φ = 5369056000.
The previous prime is 20134019981. The next prime is 20134020007. The reversal of 20134020000 is 2043102.
It is a tau number, because it is divible by the number of its divisors (120).
It is a super-2 number, since 2×201340200002 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is not an unprimeable number, because it can be changed into a prime (20134020007) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 107784 + ... + 227783.
Almost surely, 220134020000 is an apocalyptic number.
20134020000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
20134020000 is an abundant number, since it is smaller than the sum of its proper divisors (45909789216).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
20134020000 is an equidigital number, since it uses as much as digits as its factorization.
20134020000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 335600 (or 335577 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 12.
Adding to 20134020000 its reverse (2043102), we get a palindrome (20136063102).
The spelling of 20134020000 in words is "twenty billion, one hundred thirty-four million, twenty thousand".
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