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201341011301 = 1791124810119
BaseRepresentation
bin1011101110000011011…
…1000000010101100101
3201020200210122010011122
42323200313000111211
511244321244330201
6232254512343325
720355263233643
oct2734067002545
9636623563148
10201341011301
117842a82a901
1233030844b45
1315ca90b60a1
149a6023a193
155386065e1b
hex2ee0dc0565

201341011301 has 4 divisors (see below), whose sum is σ = 202465821600. Its totient is φ = 200216201004.

The previous prime is 201341011273. The next prime is 201341011367. The reversal of 201341011301 is 103110143102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201341011301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 201341011301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201341011381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 562404881 + ... + 562405238.

It is an arithmetic number, because the mean of its divisors is an integer number (50616455400).

Almost surely, 2201341011301 is an apocalyptic number.

It is an amenable number.

201341011301 is a deficient number, since it is larger than the sum of its proper divisors (1124810299).

201341011301 is a wasteful number, since it uses less digits than its factorization.

201341011301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1124810298.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 201341011301 its reverse (103110143102), we get a palindrome (304451154403).

The spelling of 201341011301 in words is "two hundred one billion, three hundred forty-one million, eleven thousand, three hundred one".

Divisors: 1 179 1124810119 201341011301