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20135441535 = 3511311392389
BaseRepresentation
bin10010110000001010…
…100111010001111111
31220222021101102002220
4102300022213101333
5312214133112120
613130004220423
71311655300116
oct226012472177
956867342086
1020135441535
1185a2a28280
123a9b39a713
131b8b77a161
14d902a0c7d
157ccac1b40
hex4b02a747f

20135441535 has 32 divisors (see below), whose sum is σ = 35258595840. Its totient is φ = 9731222400.

The previous prime is 20135441533. The next prime is 20135441561. The reversal of 20135441535 is 53514453102.

It is not a de Polignac number, because 20135441535 - 21 = 20135441533 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (33).

It is a junction number, because it is equal to n+sod(n) for n = 20135441496 and 20135441505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20135441533) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 144880 + ... + 247509.

It is an arithmetic number, because the mean of its divisors is an integer number (1101831120).

Almost surely, 220135441535 is an apocalyptic number.

20135441535 is a deficient number, since it is larger than the sum of its proper divisors (15123154305).

20135441535 is a wasteful number, since it uses less digits than its factorization.

20135441535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 392719.

The product of its (nonzero) digits is 36000, while the sum is 33.

Adding to 20135441535 its reverse (53514453102), we get a palindrome (73649894637).

The spelling of 20135441535 in words is "twenty billion, one hundred thirty-five million, four hundred forty-one thousand, five hundred thirty-five".

Divisors: 1 3 5 11 15 33 55 165 311 933 1555 3421 4665 10263 17105 51315 392389 1177167 1961945 4316279 5885835 12948837 21581395 64744185 122032979 366098937 610164895 1342362769 1830494685 4027088307 6711813845 20135441535