Base | Representation |
---|---|
bin | 111100000100000… |
… | …1001010101111100 |
3 | 12012110022222220002 |
4 | 1320020021111330 |
5 | 13111420320330 |
6 | 531553013432 |
7 | 100641425441 |
oct | 17010112574 |
9 | 5173288802 |
10 | 2015401340 |
11 | 944706947 |
12 | 482b54278 |
13 | 26170a594 |
14 | 1519479c8 |
15 | bbe05e45 |
hex | 7820957c |
2015401340 has 48 divisors (see below), whose sum is σ = 4501217952. Its totient is φ = 755367936.
The previous prime is 2015401321. The next prime is 2015401363. The reversal of 2015401340 is 431045102.
It is a super-2 number, since 2×20154013402 = 8123685122547591200, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 64124 + ... + 90236.
It is an arithmetic number, because the mean of its divisors is an integer number (93775374).
Almost surely, 22015401340 is an apocalyptic number.
2015401340 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2015401340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2250608976).
2015401340 is an abundant number, since it is smaller than the sum of its proper divisors (2485816612).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2015401340 is a wasteful number, since it uses less digits than its factorization.
2015401340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26366 (or 26364 counting only the distinct ones).
The product of its (nonzero) digits is 480, while the sum is 20.
The square root of 2015401340 is about 44893.2215373323. The cubic root of 2015401340 is about 1263.1468624481.
Adding to 2015401340 its reverse (431045102), we get a palindrome (2446446442).
The spelling of 2015401340 in words is "two billion, fifteen million, four hundred one thousand, three hundred forty".
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