Base | Representation |
---|---|
bin | 101101111011111100000001… |
… | …111111101100110010101100 |
3 | 222111022222022202122210001220 |
4 | 231323330001333230302230 |
5 | 202440033442012043200 |
6 | 1553403432110303340 |
7 | 60361154343400662 |
oct | 5573740177546254 |
9 | 874288282583056 |
10 | 202031000112300 |
11 | 59411958698357 |
12 | 1a7aab651b7b50 |
13 | 8896598164668 |
14 | 37c64d1698c32 |
15 | 185545389a4a0 |
hex | b7bf01feccac |
202031000112300 has 36 divisors (see below), whose sum is σ = 584543026992456. Its totient is φ = 53874933363200.
The previous prime is 202031000112289. The next prime is 202031000112317. The reversal of 202031000112300 is 3211000130202.
It is a super-2 number, since 2×2020310001123002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 202031000112300.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 336718333221 + ... + 336718333820.
It is an arithmetic number, because the mean of its divisors is an integer number (16237306305346).
Almost surely, 2202031000112300 is an apocalyptic number.
202031000112300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
202031000112300 is an abundant number, since it is smaller than the sum of its proper divisors (382512026880156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
202031000112300 is a wasteful number, since it uses less digits than its factorization.
202031000112300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 673436667058 (or 673436667051 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 202031000112300 its reverse (3211000130202), we get a palindrome (205242000242502).
The spelling of 202031000112300 in words is "two hundred two trillion, thirty-one billion, one hundred twelve thousand, three hundred".
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