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202213101103 = 1323676297997
BaseRepresentation
bin1011110001010011010…
…1110000111000101111
3201022221120121212110221
42330110311300320233
511303113023213403
6232521224312211
720416012666546
oct2742465607057
9638846555427
10202213101103
1178838029882
1233234912667
13160b7989a60
149b03dad15d
1553d78ccdbd
hex2f14d70e2f

202213101103 has 8 divisors (see below), whose sum is σ = 227236127328. Its totient is φ = 178542670944.

The previous prime is 202213101089. The next prime is 202213101191. The reversal of 202213101103 is 301101312202.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 202213101103 - 25 = 202213101071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (202213101193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 338148700 + ... + 338149297.

It is an arithmetic number, because the mean of its divisors is an integer number (28404515916).

Almost surely, 2202213101103 is an apocalyptic number.

202213101103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

202213101103 is a deficient number, since it is larger than the sum of its proper divisors (25023026225).

202213101103 is a wasteful number, since it uses less digits than its factorization.

202213101103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 676298033.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 202213101103 its reverse (301101312202), we get a palindrome (503314413305).

The spelling of 202213101103 in words is "two hundred two billion, two hundred thirteen million, one hundred one thousand, one hundred three".

Divisors: 1 13 23 299 676297997 8791873961 15554853931 202213101103