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20311302000000 = 27356112101277
BaseRepresentation
bin1001001111001000101111…
…11100001100110110000000
32122220202000120002121202110
410213210113330030312000
510130240021303000000
6111110514444215320
74164304666246464
oct447442774146600
978822016077673
1020311302000000
116520a7a512200
122340571b3a540
13b444697881bb
145031024044a4
1525352488a850
hex127917f0cd80

20311302000000 has 1344 divisors, whose sum is σ = 75131361743760. Its totient is φ = 4857600000000.

The previous prime is 20311301999999. The next prime is 20311302000001. The reversal of 20311302000000 is 20311302.

It is a happy number.

It is an interprime number because it is at equal distance from previous prime (20311301999999) and next prime (20311302000001).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 20311302000000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20311302000001) by changing a digit.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 73325999862 + ... + 73326000138.

Almost surely, 220311302000000 is an apocalyptic number.

20311302000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20311302000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (37565680871880).

20311302000000 is an abundant number, since it is smaller than the sum of its proper divisors (54820059743760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20311302000000 is an equidigital number, since it uses as much as digits as its factorization.

20311302000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447 (or 399 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 20311302000000 its reverse (20311302), we get a palindrome (20311322311302).

20311302000000 divided by its reverse (20311302) gives a 6-th power (1000000 = 106).

It can be divided in two parts, 2031 and 1302000000, that added together give a palindrome (1302002031).

The spelling of 20311302000000 in words is "twenty trillion, three hundred eleven billion, three hundred two million", and thus it is an aban number.