Base | Representation |
---|---|
bin | 101110011001001011001010… |
… | …111000101001011101100100 |
3 | 222202110001012210120122220102 |
4 | 232121023022320221131210 |
5 | 203220443131233230200 |
6 | 2001542423122523232 |
7 | 60656261250432662 |
oct | 5631131270513544 |
9 | 882401183518812 |
10 | 204040120211300 |
11 | 5a016a245a953a |
12 | 1aa74413506518 |
13 | 89b0b93008cc9 |
14 | 38558474a3c32 |
15 | 188c8423796d5 |
hex | b992cae29764 |
204040120211300 has 72 divisors (see below), whose sum is σ = 443828022521856. Its totient is φ = 81420511772160.
The previous prime is 204040120211281. The next prime is 204040120211359. The reversal of 204040120211300 is 3112021040402.
204040120211300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 515201957 + ... + 515597843.
Almost surely, 2204040120211300 is an apocalyptic number.
204040120211300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
204040120211300 is an abundant number, since it is smaller than the sum of its proper divisors (239787902310556).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
204040120211300 is a wasteful number, since it uses less digits than its factorization.
204040120211300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 408237 (or 408230 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 204040120211300 its reverse (3112021040402), we get a palindrome (207152141251702).
The spelling of 204040120211300 in words is "two hundred four trillion, forty billion, one hundred twenty million, two hundred eleven thousand, three hundred".
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