210012012013 has 2 divisors, whose sum is σ = 210012012014. Its totient is φ = 210012012012.

The previous prime is 210012012011. The next prime is 210012012031. The reversal of 210012012013 is 310210210012.

Together with next prime (210012012031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 142870392324 + 67141619689 = 377982^2 + 259117^2 .

It is a cyclic number.

It is not a de Polignac number, because 210012012013 - 2¹ = 210012012011 is a prime.

Together with 210012012011, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 210012011984 and 210012012002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (210012012011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105006006006 + 105006006007.

It is an arithmetic number, because the mean of its divisors is an integer number (105006006007).

Almost surely, 2^210012012013 is an apocalyptic number.

It is an amenable number.

210012012013 is a deficient number, since it is larger than the sum of its proper divisors (1).

210012012013 is an equidigital number, since it uses as much as digits as its factorization.

210012012013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 210012012013 its reverse (310210210012), we get a palindrome (520222222025).

The spelling of 210012012013 in words is "two hundred ten billion, twelve million, twelve thousand, thirteen".