Base | Representation |
---|---|
bin | 11110101101010001110… |
… | …010011010011010001111 |
3 | 21110201210112200101102102 |
4 | 132231101302122122033 |
5 | 234033142441042312 |
6 | 4253225113145315 |
7 | 305312515334336 |
oct | 36552162323217 |
9 | 7421715611372 |
10 | 2110201112207 |
11 | 743a27573531 |
12 | 2a0b7a0bb23b |
13 | 123cb6617886 |
14 | 741c4664d1d |
15 | 39d57a9dec2 |
hex | 1eb51c9a68f |
2110201112207 has 2 divisors, whose sum is σ = 2110201112208. Its totient is φ = 2110201112206.
The previous prime is 2110201112083. The next prime is 2110201112209. The reversal of 2110201112207 is 7022111020112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2110201112207 - 214 = 2110201095823 is a prime.
Together with 2110201112209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2110201112209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055100556103 + 1055100556104.
It is an arithmetic number, because the mean of its divisors is an integer number (1055100556104).
Almost surely, 22110201112207 is an apocalyptic number.
2110201112207 is a deficient number, since it is larger than the sum of its proper divisors (1).
2110201112207 is an equidigital number, since it uses as much as digits as its factorization.
2110201112207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 2110201112207 its reverse (7022111020112), we get a palindrome (9132312132319).
The spelling of 2110201112207 in words is "two trillion, one hundred ten billion, two hundred one million, one hundred twelve thousand, two hundred seven".
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