Base | Representation |
---|---|
bin | 101111111110111010001010… |
… | …011001110101110010101000 |
3 | 1000200012101112022112212212110 |
4 | 233332322022121311302220 |
5 | 210130013442224321100 |
6 | 2024454225441042320 |
7 | 62310334661100042 |
oct | 5776721231656250 |
9 | 1020171468485773 |
10 | 211031245151400 |
11 | 61271937350a33 |
12 | 1b8033290263a0 |
13 | 909a212a1a9ab |
14 | 3a17d76b28a92 |
15 | 195e61882b250 |
hex | bfee8a675ca8 |
211031245151400 has 96 divisors (see below), whose sum is σ = 658972019787840. Its totient is φ = 55864232271360.
The previous prime is 211031245151387. The next prime is 211031245151477. The reversal of 211031245151400 is 4151542130112.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1283562844 + ... + 1283727243.
It is an arithmetic number, because the mean of its divisors is an integer number (6864291872790).
Almost surely, 2211031245151400 is an apocalyptic number.
211031245151400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
211031245151400 is an abundant number, since it is smaller than the sum of its proper divisors (447940774636440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211031245151400 is a wasteful number, since it uses less digits than its factorization.
211031245151400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2567290243 (or 2567290234 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 211031245151400 its reverse (4151542130112), we get a palindrome (215182787281512).
The spelling of 211031245151400 in words is "two hundred eleven trillion, thirty-one billion, two hundred forty-five million, one hundred fifty-one thousand, four hundred".
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