Base | Representation |
---|---|
bin | 1100010010011110111… |
… | …0111011101101001111 |
3 | 202011221022112211101211 |
4 | 3010213232323231033 |
5 | 11424333210341421 |
6 | 240553122315251 |
7 | 21152515331251 |
oct | 3044756735517 |
9 | 664838484354 |
10 | 211120012111 |
11 | 81598819958 |
12 | 34abb7b8b27 |
13 | 16ba70760b8 |
14 | a30acb1cd1 |
15 | 575981c9e1 |
hex | 3127bbbb4f |
211120012111 has 2 divisors, whose sum is σ = 211120012112. Its totient is φ = 211120012110.
The previous prime is 211120012091. The next prime is 211120012127. The reversal of 211120012111 is 111210021112.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211120012111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211120012091 and 211120012100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211120012711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105560006055 + 105560006056.
It is an arithmetic number, because the mean of its divisors is an integer number (105560006056).
Almost surely, 2211120012111 is an apocalyptic number.
211120012111 is a deficient number, since it is larger than the sum of its proper divisors (1).
211120012111 is an equidigital number, since it uses as much as digits as its factorization.
211120012111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 211120012111 its reverse (111210021112), we get a palindrome (322330033223).
Subtracting from 211120012111 its reverse (111210021112), we obtain a palindrome (99909990999).
The spelling of 211120012111 in words is "two hundred eleven billion, one hundred twenty million, twelve thousand, one hundred eleven".
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