Search a number
-
+
211131300 = 223526011171
BaseRepresentation
bin11001001010110…
…01101110100100
3112201021120200210
430211121232210
5413022200200
632541135420
75142405102
oct1445315644
9481246623
10211131300
11a91a6086
125a85a570
1334983a83
142007cc72
1513807650
hexc959ba4

211131300 has 72 divisors (see below), whose sum is σ = 612412192. Its totient is φ = 56160000.

The previous prime is 211131289. The next prime is 211131307. The reversal of 211131300 is 3131112.

211131300 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (211131307) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 179715 + ... + 180885.

Almost surely, 2211131300 is an apocalyptic number.

211131300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211131300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (306206096).

211131300 is an abundant number, since it is smaller than the sum of its proper divisors (401280892).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211131300 is a wasteful number, since it uses less digits than its factorization.

211131300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1789 (or 1782 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

The square root of 211131300 is about 14530.3578758405. The cubic root of 211131300 is about 595.4576428775.

Adding to 211131300 its reverse (3131112), we get a palindrome (214262412).

It can be divided in two parts, 2111 and 31300, that added together give a triangular number (33411 = T258).

The spelling of 211131300 in words is "two hundred eleven million, one hundred thirty-one thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 75 100 150 300 601 1171 1202 1803 2342 2404 3005 3513 3606 4684 5855 6010 7026 7212 9015 11710 12020 14052 15025 17565 18030 23420 29275 30050 35130 36060 45075 58550 60100 70260 87825 90150 117100 175650 180300 351300 703771 1407542 2111313 2815084 3518855 4222626 7037710 8445252 10556565 14075420 17594275 21113130 35188550 42226260 52782825 70377100 105565650 211131300