Base | Representation |
---|---|
bin | 10011101010011100… |
… | …001111001101000011 |
3 | 2000111102002122022110 |
4 | 103222130033031003 |
5 | 321214430440120 |
6 | 13411011510403 |
7 | 1345126505061 |
oct | 235234171503 |
9 | 60442078273 |
10 | 21113140035 |
11 | 8a548a9669 |
12 | 41128b8403 |
13 | 1cb61a9490 |
14 | 1044085031 |
15 | 83884a2e0 |
hex | 4ea70f343 |
21113140035 has 64 divisors (see below), whose sum is σ = 37377438336. Its totient is φ = 10110566400.
The previous prime is 21113140033. The next prime is 21113140073. The reversal of 21113140035 is 53004131112.
It is not a de Polignac number, because 21113140035 - 21 = 21113140033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21113139993 and 21113140020.
It is not an unprimeable number, because it can be changed into a prime (21113140033) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2818495 + ... + 2825975.
It is an arithmetic number, because the mean of its divisors is an integer number (584022474).
Almost surely, 221113140035 is an apocalyptic number.
21113140035 is a deficient number, since it is larger than the sum of its proper divisors (16264298301).
21113140035 is a wasteful number, since it uses less digits than its factorization.
21113140035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7896.
The product of its (nonzero) digits is 360, while the sum is 21.
Adding to 21113140035 its reverse (53004131112), we get a palindrome (74117271147).
The spelling of 21113140035 in words is "twenty-one billion, one hundred thirteen million, one hundred forty thousand, thirty-five".
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