Base | Representation |
---|---|
bin | 110000000000011001001110… |
… | …101011101011110101001101 |
3 | 1000200120011000020220222001112 |
4 | 300000121032223223311031 |
5 | 210133202021014130331 |
6 | 2025013150451021405 |
7 | 62320610360352011 |
oct | 6000311653536515 |
9 | 1020504006828045 |
10 | 211133322411341 |
11 | 613011592a3190 |
12 | 1b81b07659a865 |
13 | 90a6a2c9b5915 |
14 | 3a1cc9b9d6541 |
15 | 19620e00da32b |
hex | c0064eaebd4d |
211133322411341 has 4 divisors (see below), whose sum is σ = 230327260812384. Its totient is φ = 191939384010300.
The previous prime is 211133322411337. The next prime is 211133322411353. The reversal of 211133322411341 is 143114223331112.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 211133322411341 - 22 = 211133322411337 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 211133322411298 and 211133322411307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211133322411331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9596969200505 + ... + 9596969200526.
It is an arithmetic number, because the mean of its divisors is an integer number (57581815203096).
Almost surely, 2211133322411341 is an apocalyptic number.
It is an amenable number.
211133322411341 is a deficient number, since it is larger than the sum of its proper divisors (19193938401043).
211133322411341 is a wasteful number, since it uses less digits than its factorization.
211133322411341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19193938401042.
The product of its digits is 10368, while the sum is 32.
Adding to 211133322411341 its reverse (143114223331112), we get a palindrome (354247545742453).
The spelling of 211133322411341 in words is "two hundred eleven trillion, one hundred thirty-three billion, three hundred twenty-two million, four hundred eleven thousand, three hundred forty-one".
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