| Base | Representation |
|---|---|
| bin | 1100010010110010100… |
| … | …0000111101000000000 |
| 3 | 202012011001000221021110 |
| 4 | 3010230220013220000 |
| 5 | 11430020220041000 |
| 6 | 241005214123320 |
| 7 | 21154533221445 |
| oct | 3045450075000 |
| 9 | 665131027243 |
| 10 | 211202112000 |
| 11 | 816300a4800 |
| 12 | 34b231b0540 |
| 13 | 16bbb090209 |
| 14 | a317b639cc |
| 15 | 5761b38850 |
| hex | 312ca07a00 |
211202112000 has 480 divisors, whose sum is σ = 771918219072. Its totient is φ = 51194880000.
The previous prime is 211202111987. The next prime is 211202112019. The reversal of 211202112000 is 211202112.
It is a tau number, because it is divible by the number of its divisors (480).
It is a super-2 number, since 2×2112021120002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 23227455 + ... + 23236545.
Almost surely, 2211202112000 is an apocalyptic number.
211202112000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 211202112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (385959109536).
211202112000 is an abundant number, since it is smaller than the sum of its proper divisors (560716107072).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211202112000 is an equidigital number, since it uses as much as digits as its factorization.
211202112000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9149 (or 9112 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 12.
Adding to 211202112000 its reverse (211202112), we get a palindrome (211413314112).
211202112000 divided by its reverse (211202112) gives a cube (1000 = 103).
It can be divided in two parts, 21120 and 2112000, that multiplied together give a square (44605440000 = 2112002).
The spelling of 211202112000 in words is "two hundred eleven billion, two hundred two million, one hundred twelve thousand".
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