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211413314112 = 2637113139091
BaseRepresentation
bin1100010011100100110…
…1110010101001000000
3202012200202110010002220
43010321031302221000
511430433302022422
6241042201011040
721163006343160
oct3047115625100
9665622403086
10211413314112
1181729339000
1234b81a83a80
1316c22a6a290
14a337c205a0
155775456e5c
hex3139372a40

211413314112 has 448 divisors, whose sum is σ = 757324904448. Its totient is φ = 50682931200.

The previous prime is 211413314087. The next prime is 211413314141.

211413314112 is nontrivially palindromic in base 10.

It is a tau number, because it is divible by the number of its divisors (448).

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a nude number because it is divisible by every one of its digits.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23250687 + ... + 23259777.

It is an arithmetic number, because the mean of its divisors is an integer number (1690457376).

Almost surely, 2211413314112 is an apocalyptic number.

211413314112 is a gapful number since it is divisible by the number (22) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211413314112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (378662452224).

211413314112 is an abundant number, since it is smaller than the sum of its proper divisors (545911590336).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211413314112 is a wasteful number, since it uses less digits than its factorization.

211413314112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9159 (or 9127 counting only the distinct ones).

The product of its digits is 576, while the sum is 24.

211413314112 divided by its sum of digits (24) gives a palindrome (8808888088).

It can be divided in two parts, 211413 and 314112, that added together give a palindrome (525525).

The spelling of 211413314112 in words is "two hundred eleven billion, four hundred thirteen million, three hundred fourteen thousand, one hundred twelve".