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2112111100102 = 21056055550051
BaseRepresentation
bin11110101111000011101…
…000011100000011000110
321110220201122122211020211
4132233003220130003012
5234101100420200402
64254142422550034
7305411040063223
oct36570350340306
97426648584224
102112111100102
11744817720723
122a141189831a
1312422c237623
14743261ac94a
1539e1a5d14d7
hex1ebc3a1c0c6

2112111100102 has 4 divisors (see below), whose sum is σ = 3168166650156. Its totient is φ = 1056055550050.

The previous prime is 2112111100093. The next prime is 2112111100111. The reversal of 2112111100102 is 2010011112112.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (2112111100093) and next prime (2112111100111).

It is a super-2 number, since 2×21121111001022 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 528027775024 + ... + 528027775027.

It is an arithmetic number, because the mean of its divisors is an integer number (792041662539).

Almost surely, 22112111100102 is an apocalyptic number.

2112111100102 is a deficient number, since it is larger than the sum of its proper divisors (1056055550054).

2112111100102 is a wasteful number, since it uses less digits than its factorization.

2112111100102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1056055550053.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 2112111100102 its reverse (2010011112112), we get a palindrome (4122122212214).

The spelling of 2112111100102 in words is "two trillion, one hundred twelve billion, one hundred eleven million, one hundred thousand, one hundred two".

Divisors: 1 2 1056055550051 2112111100102