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21121300000 = 2555211213
BaseRepresentation
bin10011101010111011…
…010111011000100000
32000111222110012200101
4103222323113120200
5321224023100000
613411502432144
71345256042053
oct235273273040
960458405611
1021121300000
118a59472339
124115592654
131cb7aa5668
1410451aaa9a
1583940ce6a
hex4eaed7620

21121300000 has 72 divisors (see below), whose sum is σ = 51975118692. Its totient is φ = 8448480000.

The previous prime is 21121299949. The next prime is 21121300003. The reversal of 21121300000 is 312112.

It can be written as a sum of positive squares in 6 ways, for example, as 8631896464 + 12489403536 = 92908^2 + 111756^2 .

It is a super-2 number, since 2×211213000002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a self number, because there is not a number n which added to its sum of digits gives 21121300000.

It is not an unprimeable number, because it can be changed into a prime (21121300003) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5607 + ... + 205606.

Almost surely, 221121300000 is an apocalyptic number.

21121300000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21121300000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25987559346).

21121300000 is an abundant number, since it is smaller than the sum of its proper divisors (30853818692).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21121300000 is an frugal number, since it uses more digits than its factorization.

21121300000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 211248 (or 211220 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 10.

Adding to 21121300000 its reverse (312112), we get a palindrome (21121612112).

The spelling of 21121300000 in words is "twenty-one billion, one hundred twenty-one million, three hundred thousand".

Divisors: 1 2 4 5 8 10 16 20 25 32 40 50 80 100 125 160 200 250 400 500 625 800 1000 1250 2000 2500 3125 4000 5000 6250 10000 12500 20000 25000 50000 100000 211213 422426 844852 1056065 1689704 2112130 3379408 4224260 5280325 6758816 8448520 10560650 16897040 21121300 26401625 33794080 42242600 52803250 84485200 105606500 132008125 168970400 211213000 264016250 422426000 528032500 660040625 844852000 1056065000 1320081250 2112130000 2640162500 4224260000 5280325000 10560650000 21121300000