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2112222112000 = 285371113234761
BaseRepresentation
bin11110101111001010001…
…111111010100100000000
321110221000101112210221121
4132233022033322210000
5234101312330041000
64254201430202024
7305413555501120
oct36571217724400
97427011483847
102112222112000
117448743535a0
122a1442ab3314
13124249235440
1474336c28c80
1539e2520db1a
hex1ebca3fa900

2112222112000 has 2304 divisors, whose sum is σ = 7652246224896. Its totient is φ = 559595520000.

The previous prime is 2112222111997. The next prime is 2112222112001. The reversal of 2112222112000 is 2112222112.

It is a happy number.

It is a super-2 number, since 2×21122221120002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is not an unprimeable number, because it can be changed into a prime (2112222112001) by changing a digit.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 34626591970 + ... + 34626592030.

It is an arithmetic number, because the mean of its divisors is an integer number (3321287424).

Almost surely, 22112222112000 is an apocalyptic number.

2112222112000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2112222112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3826123112448).

2112222112000 is an abundant number, since it is smaller than the sum of its proper divisors (5540024112896).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2112222112000 is a wasteful number, since it uses less digits than its factorization.

2112222112000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 193 (or 169 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 2112222112000 its reverse (2112222112), we get a palindrome (2114334334112).

2112222112000 divided by its reverse (2112222112) gives a cube (1000 = 103).

It can be divided in two parts, 2112222 and 112000, that added together give a palindrome (2224222).

The spelling of 2112222112000 in words is "two trillion, one hundred twelve billion, two hundred twenty-two million, one hundred twelve thousand".