211230504135 has 48 divisors (see below), whose sum is σ = 436830444000. Its totient is φ = 96562513152.

The previous prime is 211230504113. The next prime is 211230504137. The reversal of 211230504135 is 531405032112.

211230504135 is a `hidden beast` number, since 2 + 1 + 1 + 23 + 0 + 504 + 135 = 666.

211230504135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 211230504135 - 2¹⁰ = 211230503111 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 211230504099 and 211230504108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211230504137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15959410 + ... + 15972639.

It is an arithmetic number, because the mean of its divisors is an integer number (9100634250).

Almost surely, 2^211230504135 is an apocalyptic number.

211230504135 is an abundant number, since it is smaller than the sum of its proper divisors (225599939865).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211230504135 is a wasteful number, since it uses less digits than its factorization.

211230504135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31932077 (or 31932064 counting only the distinct ones).

The product of its (nonzero) digits is 3600, while the sum is 27.

Adding to 211230504135 its reverse (531405032112), we get a palindrome (742635536247).

The spelling of 211230504135 in words is "two hundred eleven billion, two hundred thirty million, five hundred four thousand, one hundred thirty-five".