Base | Representation |
---|---|
bin | 1001100110110011100011… |
… | …01101010110010011101110 |
3 | 2202210111011200121202222000 |
4 | 10303121301231112103232 |
5 | 10232101043024444430 |
6 | 112532253142433130 |
7 | 4310125132524102 |
oct | 463316155262356 |
9 | 82714150552860 |
10 | 21124556874990 |
11 | 6804968704738 |
12 | 24520b74327a6 |
13 | ba3063864b6a |
14 | 530610cbd902 |
15 | 269771677e60 |
hex | 133671b564ee |
21124556874990 has 32 divisors (see below), whose sum is σ = 56332151667360. Its totient is φ = 5633215166592.
The previous prime is 21124556874977. The next prime is 21124556875001. The reversal of 21124556874990 is 9947865542112.
21124556874990 is a `hidden beast` number, since 2 + 1 + 1 + 2 + 4 + 556 + 8 + 74 + 9 + 9 + 0 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39119549499 + ... + 39119550038.
It is an arithmetic number, because the mean of its divisors is an integer number (1760379739605).
Almost surely, 221124556874990 is an apocalyptic number.
21124556874990 is an abundant number, since it is smaller than the sum of its proper divisors (35207594792370).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21124556874990 is a wasteful number, since it uses less digits than its factorization.
21124556874990 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78239099553 (or 78239099547 counting only the distinct ones).
The product of its (nonzero) digits is 43545600, while the sum is 63.
The spelling of 21124556874990 in words is "twenty-one trillion, one hundred twenty-four billion, five hundred fifty-six million, eight hundred seventy-four thousand, nine hundred ninety".
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