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211300103 = 72234332
BaseRepresentation
bin11001001100000…
…10111100000111
3112201121011020202
430212002330013
5413043100403
632544521115
75144010200
oct1446027407
9481534222
10211300103
11a9300993
125a92019b
1334a12861
14200c45a7
151383c688
hexc982f07

211300103 has 18 divisors (see below), whose sum is σ = 257078664. Its totient is φ = 172839744.

The previous prime is 211300099. The next prime is 211300127. The reversal of 211300103 is 301003112.

It is not a de Polignac number, because 211300103 - 22 = 211300099 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211300163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 487775 + ... + 488207.

It is an arithmetic number, because the mean of its divisors is an integer number (14282148).

Almost surely, 2211300103 is an apocalyptic number.

211300103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

211300103 is a deficient number, since it is larger than the sum of its proper divisors (45778561).

211300103 is an frugal number, since it uses more digits than its factorization.

211300103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 903 (or 463 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 211300103 is about 14536.1653471609. The cubic root of 211300103 is about 595.6162933801.

Adding to 211300103 its reverse (301003112), we get a palindrome (512303215).

The spelling of 211300103 in words is "two hundred eleven million, three hundred thousand, one hundred three".

Divisors: 1 7 23 49 161 433 1127 3031 9959 21217 69713 187489 487991 1312423 4312247 9186961 30185729 211300103