Base | Representation |
---|---|
bin | 11110101111111111001… |
… | …100100000111011001000 |
3 | 21111000022022001011211122 |
4 | 132233333030200323020 |
5 | 234110122231204000 |
6 | 4254425521414412 |
7 | 305444563103006 |
oct | 36577714407310 |
9 | 7430268034748 |
10 | 2113110413000 |
11 | 74518a815254 |
12 | 2a165049a408 |
13 | 12435b293b32 |
14 | 743bcbbba76 |
15 | 39e781c9085 |
hex | 1ebff320ec8 |
2113110413000 has 64 divisors (see below), whose sum is σ = 4965196270320. Its totient is φ = 841736832000.
The previous prime is 2113110412999. The next prime is 2113110413041. The reversal of 2113110413000 is 3140113112.
It can be written as a sum of positive squares in 8 ways, for example, as 21286226404 + 2091824186596 = 145898^2 + 1446314^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 2113110413000.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4143047 + ... + 4625046.
Almost surely, 22113110413000 is an apocalyptic number.
2113110413000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2113110413000 is an abundant number, since it is smaller than the sum of its proper divisors (2852085857320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2113110413000 is a wasteful number, since it uses less digits than its factorization.
2113110413000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8768355 (or 8768341 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2113110413000 its reverse (3140113112), we get a palindrome (2116250526112).
The spelling of 2113110413000 in words is "two trillion, one hundred thirteen billion, one hundred ten million, four hundred thirteen thousand".
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