Base | Representation |
---|---|
bin | 11110110000000100100… |
… | …110001111011111110000 |
3 | 21111000112121120200102121 |
4 | 132300010212033133300 |
5 | 234110313431342230 |
6 | 4254442520124024 |
7 | 305450043332464 |
oct | 36600446173760 |
9 | 7430477520377 |
10 | 2113201043440 |
11 | 745226997243 |
12 | 2a1676906614 |
13 | 124373ca6a06 |
14 | 743cac504a4 |
15 | 39e8112c77a |
hex | 1ec0498f7f0 |
2113201043440 has 40 divisors (see below), whose sum is σ = 4913253455760. Its totient is φ = 845269917696.
The previous prime is 2113201043417. The next prime is 2113201043521. The reversal of 2113201043440 is 443401023112.
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11242551 + ... + 11428969.
It is an arithmetic number, because the mean of its divisors is an integer number (122831336394).
Almost surely, 22113201043440 is an apocalyptic number.
2113201043440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
2113201043440 is an abundant number, since it is smaller than the sum of its proper divisors (2800052412320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2113201043440 is a wasteful number, since it uses less digits than its factorization.
2113201043440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 328129 (or 328123 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 2113201043440 its reverse (443401023112), we get a palindrome (2556602066552).
The spelling of 2113201043440 in words is "two trillion, one hundred thirteen billion, two hundred one million, forty-three thousand, four hundred forty".
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