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212013101300 = 22527111317314019
BaseRepresentation
bin1100010101110011110…
…1110011000011110100
3202021020120001110110012
43011130331303003310
511433200323220200
6241221504315352
721213611424650
oct3053475630364
9667216043405
10212013101300
1181a06960aa0
123510a912b58
1316cba0c0040
14a39374da60
1557ace31a35
hex315cf730f4

212013101300 has 576 divisors, whose sum is σ = 675316776960. Its totient is φ = 55544832000.

The previous prime is 212013101273. The next prime is 212013101309. The reversal of 212013101300 is 3101310212.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212013101309) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 52750691 + ... + 52754709.

It is an arithmetic number, because the mean of its divisors is an integer number (1172424960).

Almost surely, 2212013101300 is an apocalyptic number.

212013101300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 212013101300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (337658388480).

212013101300 is an abundant number, since it is smaller than the sum of its proper divisors (463303675660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

212013101300 is a wasteful number, since it uses less digits than its factorization.

212013101300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4112 (or 4105 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 212013101300 its reverse (3101310212), we get a palindrome (215114411512).

It can be divided in two parts, 212013 and 101300, that added together give a palindrome (313313).

The spelling of 212013101300 in words is "two hundred twelve billion, thirteen million, one hundred one thousand, three hundred".