21311003141 has 2 divisors, whose sum is σ = 21311003142. Its totient is φ = 21311003140.

The previous prime is 21311003113. The next prime is 21311003143. The reversal of 21311003141 is 14130011312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15964322500 + 5346680641 = 126350^2 + 73121^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21311003141 is a prime.

Together with 21311003143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21311003143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10655501570 + 10655501571.

It is an arithmetic number, because the mean of its divisors is an integer number (10655501571).

Almost surely, 2^21311003141 is an apocalyptic number.

It is an amenable number.

21311003141 is a deficient number, since it is larger than the sum of its proper divisors (1).

21311003141 is an equidigital number, since it uses as much as digits as its factorization.

21311003141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 21311003141 its reverse (14130011312), we get a palindrome (35441014453).

The spelling of 21311003141 in words is "twenty-one billion, three hundred eleven million, three thousand, one hundred forty-one".