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21311400000 = 26355113229
BaseRepresentation
bin10011110110010000…
…100010100001000000
32001000020011021212010
4103312100202201000
5322121204300000
613442413132520
71353054624342
oct236620424100
961006137763
1021311400000
119046803280
12416918a140
1320182a4777
141062533292
1584ae5dd50
hex4f6422840

21311400000 has 336 divisors, whose sum is σ = 76909452480. Its totient is φ = 5164800000.

The previous prime is 21311399981. The next prime is 21311400013. The reversal of 21311400000 is 411312.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6598386 + ... + 6601614.

It is an arithmetic number, because the mean of its divisors is an integer number (228897180).

Almost surely, 221311400000 is an apocalyptic number.

21311400000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21311400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (38454726240).

21311400000 is an abundant number, since it is smaller than the sum of its proper divisors (55598052480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21311400000 is an equidigital number, since it uses as much as digits as its factorization.

21311400000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3280 (or 3250 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 21311400000 its reverse (411312), we get a palindrome (21311811312).

The spelling of 21311400000 in words is "twenty-one billion, three hundred eleven million, four hundred thousand".