Base | Representation |
---|---|
bin | 110000011111000110111101… |
… | …101011001110101000011111 |
3 | 1000222000221001221120222202011 |
4 | 300133012331223032220133 |
5 | 210422242214424130210 |
6 | 2033310540350212051 |
7 | 62626241305546021 |
oct | 6037067553165037 |
9 | 1028027057528664 |
10 | 213244013505055 |
11 | 61a45307400005 |
12 | 1bb001507b4027 |
13 | 91caa93988480 |
14 | 3a930cb366011 |
15 | 199be75bc3d8a |
hex | c1f1bdacea1f |
213244013505055 has 64 divisors (see below), whose sum is σ = 295127792064000. Its totient is φ = 146591177144832.
The previous prime is 213244013504999. The next prime is 213244013505071. The reversal of 213244013505055 is 550505310442312.
It is a cyclic number.
It is not a de Polignac number, because 213244013505055 - 27 = 213244013504927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 213244013504999 and 213244013505017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 164685784 + ... + 165975586.
It is an arithmetic number, because the mean of its divisors is an integer number (4611371751000).
Almost surely, 2213244013505055 is an apocalyptic number.
213244013505055 is a deficient number, since it is larger than the sum of its proper divisors (81883778558945).
213244013505055 is a wasteful number, since it uses less digits than its factorization.
213244013505055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1292168.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 213244013505055 its reverse (550505310442312), we get a palindrome (763749323947367).
The spelling of 213244013505055 in words is "two hundred thirteen trillion, two hundred forty-four billion, thirteen million, five hundred five thousand, fifty-five".
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