Base | Representation |
---|---|
bin | 101000101011… |
… | …0011001111001 |
3 | 1111010102222212 |
4 | 1101112121321 |
5 | 20424403213 |
6 | 2041024505 |
7 | 346156163 |
oct | 121263171 |
9 | 44112885 |
10 | 21325433 |
11 | 11046128 |
12 | 7185135 |
13 | 45587cc |
14 | 2b91933 |
15 | 1d139a8 |
hex | 1456679 |
21325433 has 2 divisors, whose sum is σ = 21325434. Its totient is φ = 21325432.
The previous prime is 21325397. The next prime is 21325441. The reversal of 21325433 is 33452312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20502784 + 822649 = 4528^2 + 907^2 .
It is a cyclic number.
It is not a de Polignac number, because 21325433 - 28 = 21325177 is a prime.
It is a Chen prime.
It is a plaindrome in base 16.
It is a junction number, because it is equal to n+sod(n) for n = 21325399 and 21325408.
It is not a weakly prime, because it can be changed into another prime (21385433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10662716 + 10662717.
It is an arithmetic number, because the mean of its divisors is an integer number (10662717).
Almost surely, 221325433 is an apocalyptic number.
It is an amenable number.
21325433 is a deficient number, since it is larger than the sum of its proper divisors (1).
21325433 is an equidigital number, since it uses as much as digits as its factorization.
21325433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2160, while the sum is 23.
The square root of 21325433 is about 4617.9468381522. The cubic root of 21325433 is about 277.3102693558.
Adding to 21325433 its reverse (33452312), we get a palindrome (54777745).
The spelling of 21325433 in words is "twenty-one million, three hundred twenty-five thousand, four hundred thirty-three".
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