Base | Representation |
---|---|
bin | 11111000010100111011… |
… | …000101110100011001111 |
3 | 21112220221020122220212210 |
4 | 133002213120232203033 |
5 | 234422103141243030 |
6 | 4311534350201503 |
7 | 310053335212023 |
oct | 37024730564317 |
9 | 7486836586783 |
10 | 2133112056015 |
11 | 752714166736 |
12 | 2a54b2ab3293 |
13 | 1261c80c5565 |
14 | 753593b0383 |
15 | 3a74916bbb0 |
hex | 1f0a762e8cf |
2133112056015 has 8 divisors (see below), whose sum is σ = 3412979289648. Its totient is φ = 1137659763200.
The previous prime is 2133112056007. The next prime is 2133112056017. The reversal of 2133112056015 is 5106502113312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2133112056015 - 23 = 2133112056007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2133112056017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71103735186 + ... + 71103735215.
It is an arithmetic number, because the mean of its divisors is an integer number (426622411206).
Almost surely, 22133112056015 is an apocalyptic number.
2133112056015 is a deficient number, since it is larger than the sum of its proper divisors (1279867233633).
2133112056015 is a wasteful number, since it uses less digits than its factorization.
2133112056015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142207470409.
The product of its (nonzero) digits is 5400, while the sum is 30.
Adding to 2133112056015 its reverse (5106502113312), we get a palindrome (7239614169327).
The spelling of 2133112056015 in words is "two trillion, one hundred thirty-three billion, one hundred twelve million, fifty-six thousand, fifteen".
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