Base | Representation |
---|---|
bin | 11001011100011… |
… | …10001000110000 |
3 | 112212122000220202 |
4 | 30232032020300 |
5 | 414120134440 |
6 | 33102454332 |
7 | 5201144102 |
oct | 1456161060 |
9 | 485560822 |
10 | 213443120 |
11 | aa534a80 |
12 | 5b5943a8 |
13 | 352b3107 |
14 | 204c1572 |
15 | 13b12615 |
hex | cb8e230 |
213443120 has 80 divisors (see below), whose sum is σ = 550679040. Its totient is φ = 76281600.
The previous prime is 213443107. The next prime is 213443149. The reversal of 213443120 is 21344312.
It is a tau number, because it is divible by the number of its divisors (80).
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 213443092 and 213443101.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49865 + ... + 53975.
It is an arithmetic number, because the mean of its divisors is an integer number (6883488).
Almost surely, 2213443120 is an apocalyptic number.
213443120 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 213443120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (275339520).
213443120 is an abundant number, since it is smaller than the sum of its proper divisors (337235920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213443120 is a wasteful number, since it uses less digits than its factorization.
213443120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4194 (or 4188 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
The square root of 213443120 is about 14609.6926730168. The cubic root of 213443120 is about 597.6231149816.
Adding to 213443120 its reverse (21344312), we get a palindrome (234787432).
It can be divided in two parts, 2134 and 43120, that added together give a palindrome (45254).
The spelling of 213443120 in words is "two hundred thirteen million, four hundred forty-three thousand, one hundred twenty".
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