2143481 has 2 divisors, whose sum is σ = 2143482. Its totient is φ = 2143480.

The previous prime is 2143469. The next prime is 2143483. The reversal of 2143481 is 1843412.

2143481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2131600 + 11881 = 1460^2 + 109^2 .

It is a cyclic number.

It is not a de Polignac number, because 2143481 - 2⁶ = 2143417 is a prime.

It is a super-2 number, since 2×2143481² = 9189021594722, which contains 22 as substring.

Together with 2143483, it forms a pair of twin primes.

It is a Chen prime.

It is equal to p₁₅₈₈₀₁ and since 2143481 and 158801 have the same sum of digits, it is a Honaker prime.

It is a plaindrome in base 11.

It is not a weakly prime, because it can be changed into another prime (2143483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071740 + 1071741.

It is an arithmetic number, because the mean of its divisors is an integer number (1071741).

2^2143481 is an apocalyptic number.

It is an amenable number.

2143481 is a deficient number, since it is larger than the sum of its proper divisors (1).

2143481 is an equidigital number, since it uses as much as digits as its factorization.

2143481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 768, while the sum is 23.

The square root of 2143481 is about 1464.0631816967. The cubic root of 2143481 is about 128.9357090052.

Adding to 2143481 its reverse (1843412), we get a palindrome (3986893).

The spelling of 2143481 in words is "two million, one hundred forty-three thousand, four hundred eighty-one".