Base | Representation |
---|---|
bin | 1100100001000111111… |
… | …1011101101011010111 |
3 | 202120002012220202222120 |
4 | 3020101333131223113 |
5 | 12010410323322403 |
6 | 242443120231023 |
7 | 21352100442144 |
oct | 3102177355327 |
9 | 676065822876 |
10 | 215050214103 |
11 | 8322526a87a |
12 | 35817a6b473 |
13 | 17382399bca |
14 | a5a0c573cb |
15 | 58d98a6e53 |
hex | 3211fddad7 |
215050214103 has 4 divisors (see below), whose sum is σ = 286733618808. Its totient is φ = 143366809400.
The previous prime is 215050214101. The next prime is 215050214123. The reversal of 215050214103 is 301412050512.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 215050214103 - 21 = 215050214101 is a prime.
It is a super-2 number, since 2×2150502141032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (215050214101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35841702348 + ... + 35841702353.
It is an arithmetic number, because the mean of its divisors is an integer number (71683404702).
Almost surely, 2215050214103 is an apocalyptic number.
215050214103 is a deficient number, since it is larger than the sum of its proper divisors (71683404705).
215050214103 is an equidigital number, since it uses as much as digits as its factorization.
215050214103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71683404704.
The product of its (nonzero) digits is 1200, while the sum is 24.
Adding to 215050214103 its reverse (301412050512), we get a palindrome (516462264615).
The spelling of 215050214103 in words is "two hundred fifteen billion, fifty million, two hundred fourteen thousand, one hundred three".
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