Base | Representation |
---|---|
bin | 101010111100… |
… | …0100111000101 |
3 | 1120100211120012 |
4 | 1111320213011 |
5 | 21230422432 |
6 | 2122320005 |
7 | 362236553 |
oct | 125704705 |
9 | 46324505 |
10 | 22514117 |
11 | 1178820a |
12 | 7659005 |
13 | 4883882 |
14 | 2dc0bd3 |
15 | 1e9acb2 |
hex | 15789c5 |
22514117 has 2 divisors, whose sum is σ = 22514118. Its totient is φ = 22514116.
The previous prime is 22514113. The next prime is 22514123. The reversal of 22514117 is 71141522.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12773476 + 9740641 = 3574^2 + 3121^2 .
It is a cyclic number.
It is not a de Polignac number, because 22514117 - 22 = 22514113 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 22514092 and 22514101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22514111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11257058 + 11257059.
It is an arithmetic number, because the mean of its divisors is an integer number (11257059).
Almost surely, 222514117 is an apocalyptic number.
It is an amenable number.
22514117 is a deficient number, since it is larger than the sum of its proper divisors (1).
22514117 is an equidigital number, since it uses as much as digits as its factorization.
22514117 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 560, while the sum is 23.
The square root of 22514117 is about 4744.9043193725. The cubic root of 22514117 is about 282.3698390120.
Adding to 22514117 its reverse (71141522), we get a palindrome (93655639).
The spelling of 22514117 in words is "twenty-two million, five hundred fourteen thousand, one hundred seventeen".
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