23013000035 has 4 divisors (see below), whose sum is σ = 27615600048. Its totient is φ = 18410400024.

The previous prime is 23013000019. The next prime is 23013000041. The reversal of 23013000035 is 53000031032.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 23013000035 - 2⁴ = 23013000019 is a prime.

It is a super-2 number, since 2×23013000035² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23012999977 and 23013000022.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2301299999 + ... + 2301300008.

It is an arithmetic number, because the mean of its divisors is an integer number (6903900012).

Almost surely, 2^23013000035 is an apocalyptic number.

23013000035 is a deficient number, since it is larger than the sum of its proper divisors (4602600013).

23013000035 is an equidigital number, since it uses as much as digits as its factorization.

23013000035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4602600012.

The product of its (nonzero) digits is 270, while the sum is 17.

Adding to 23013000035 its reverse (53000031032), we get a palindrome (76013031067).

The spelling of 23013000035 in words is "twenty-three billion, thirteen million, thirty-five", and thus it is an aban number and an uban number.