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2314115 = 51313533
BaseRepresentation
bin1000110100111110000011
311100120100222
420310332003
51043022430
6121333255
725445456
oct10647603
94316328
102314115
1113406a1
1293722b
136303cb
1444349d
1530a9e5
hex234f83

2314115 has 8 divisors (see below), whose sum is σ = 2798928. Its totient is φ = 1836640.

The previous prime is 2314097. The next prime is 2314121. The reversal of 2314115 is 5114132.

2314115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2314115 - 26 = 2314051 is a prime.

It is an Ulam number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2314093 and 2314102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1112 + ... + 2421.

It is an arithmetic number, because the mean of its divisors is an integer number (349866).

22314115 is an apocalyptic number.

2314115 is a deficient number, since it is larger than the sum of its proper divisors (484813).

2314115 is a wasteful number, since it uses less digits than its factorization.

2314115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3669.

The product of its digits is 120, while the sum is 17.

The square root of 2314115 is about 1521.2215486247. The cubic root of 2314115 is about 132.2700890125.

Adding to 2314115 its sum of digits (17), we get a palindrome (2314132).

Adding to 2314115 its reverse (5114132), we get a palindrome (7428247).

The spelling of 2314115 in words is "two million, three hundred fourteen thousand, one hundred fifteen".

Divisors: 1 5 131 655 3533 17665 462823 2314115