Base | Representation |
---|---|
bin | 100011011000111111010… |
… | …110000111000001000111 |
3 | 22121111110020212121221220 |
4 | 203120333112013001013 |
5 | 304321231122000210 |
6 | 5101130225411423 |
7 | 340464403020045 |
oct | 43307726070107 |
9 | 8544406777856 |
10 | 2432014250055 |
11 | 858458707085 |
12 | 333410799b73 |
13 | 148451661030 |
14 | 859d27c5395 |
15 | 433e0279c70 |
hex | 2363f587047 |
2432014250055 has 16 divisors (see below), whose sum is σ = 4190547631200. Its totient is φ = 1197299323008.
The previous prime is 2432014250009. The next prime is 2432014250089. The reversal of 2432014250055 is 5500524102342.
It is a happy number.
2432014250055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 2432014250055 - 29 = 2432014249543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2432014249998 and 2432014250025.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6235933780 + ... + 6235934169.
It is an arithmetic number, because the mean of its divisors is an integer number (261909226950).
Almost surely, 22432014250055 is an apocalyptic number.
2432014250055 is a deficient number, since it is larger than the sum of its proper divisors (1758533381145).
2432014250055 is a wasteful number, since it uses less digits than its factorization.
2432014250055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12471867970.
The product of its (nonzero) digits is 48000, while the sum is 33.
Adding to 2432014250055 its reverse (5500524102342), we get a palindrome (7932538352397).
The spelling of 2432014250055 in words is "two trillion, four hundred thirty-two billion, fourteen million, two hundred fifty thousand, fifty-five".
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