Base | Representation |
---|---|
bin | 110111110010001011111010… |
… | …100010100000010000011111 |
3 | 1012011200101211210022110220022 |
4 | 313302023322202200100133 |
5 | 224124133013224344020 |
6 | 2225444125430342355 |
7 | 102451216515624440 |
oct | 6762137242402037 |
9 | 1164611753273808 |
10 | 245341325231135 |
11 | 7119a74306aa61 |
12 | 236249614ba9bb |
13 | a6b878422c193 |
14 | 44828251a32c7 |
15 | 1d56d56b99625 |
hex | df22fa8a041f |
245341325231135 has 72 divisors (see below), whose sum is σ = 366354918615840. Its totient is φ = 154476019445760.
The previous prime is 245341325231089. The next prime is 245341325231147. The reversal of 245341325231135 is 531132523143542.
245341325231135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 245341325231135 - 236 = 245272605754399 is a prime.
It is a super-2 number, since 2×2453413252311352 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 9788801 + ... + 24217829.
Almost surely, 2245341325231135 is an apocalyptic number.
245341325231135 is a deficient number, since it is larger than the sum of its proper divisors (121013593384705).
245341325231135 is a wasteful number, since it uses less digits than its factorization.
245341325231135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14429157 (or 14429099 counting only the distinct ones).
The product of its digits is 1296000, while the sum is 44.
Adding to 245341325231135 its reverse (531132523143542), we get a palindrome (776473848374677).
The spelling of 245341325231135 in words is "two hundred forty-five trillion, three hundred forty-one billion, three hundred twenty-five million, two hundred thirty-one thousand, one hundred thirty-five".
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