2500955401300 has 36 divisors (see below), whose sum is σ = 5427143328096. Its totient is φ = 1000369237600.

The previous prime is 2500955401283. The next prime is 2500955401309. The reversal of 2500955401300 is 31045590052.

It is a super-4 number, since 4×2500955401300⁴ (a number of 51 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2500955401309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12763065 + ... + 12957535.

It is an arithmetic number, because the mean of its divisors is an integer number (150753981336).

Almost surely, 2^{2500955401300} is an apocalyptic number.

2500955401300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2500955401300 is an abundant number, since it is smaller than the sum of its proper divisors (2926187926796).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2500955401300 is a wasteful number, since it uses less digits than its factorization.

2500955401300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 323088 (or 323081 counting only the distinct ones).

The product of its (nonzero) digits is 27000, while the sum is 34.

The spelling of 2500955401300 in words is "two trillion, five hundred billion, nine hundred fifty-five million, four hundred one thousand, three hundred".