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25103000000 = 2656131931
BaseRepresentation
bin10111011000010000…
…010110000111000000
32101210110201112020202
4113120100112013000
5402402332000000
615310540224332
71546034656631
oct273020260700
971713645222
1025103000000
11a711a974a1
124a46b3b0a8
1324a098a670
141301d19888
159bdc6add5
hex5d84161c0

25103000000 has 196 divisors, whose sum is σ = 67090859976. Its totient is φ = 9264000000.

The previous prime is 25102999997. The next prime is 25103000017. The reversal of 25103000000 is 30152.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 12999035 + ... + 13000965.

It is an arithmetic number, because the mean of its divisors is an integer number (342300306).

Almost surely, 225103000000 is an apocalyptic number.

25103000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 25103000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (33545429988).

25103000000 is an abundant number, since it is smaller than the sum of its proper divisors (41987859976).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

25103000000 is an frugal number, since it uses more digits than its factorization.

25103000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1986 (or 1951 counting only the distinct ones).

The product of its (nonzero) digits is 30, while the sum is 11.

Adding to 25103000000 its reverse (30152), we get a palindrome (25103030152).

The spelling of 25103000000 in words is "twenty-five billion, one hundred three million", and thus it is an aban number.