Base | Representation |
---|---|
bin | 101111111011… |
… | …1010000010111 |
3 | 1202021201220000 |
4 | 1133313100113 |
5 | 22413130012 |
6 | 2254342343 |
7 | 423413220 |
oct | 137672027 |
9 | 52251800 |
10 | 25130007 |
11 | 13204601 |
12 | 84ba9b3 |
13 | 528b436 |
14 | 34a2247 |
15 | 2315ddc |
hex | 17f7417 |
25130007 has 80 divisors (see below), whose sum is σ = 46835712. Its totient is φ = 13115520.
The previous prime is 25129999. The next prime is 25130011. The reversal of 25130007 is 70003152.
It is not a de Polignac number, because 25130007 - 23 = 25129999 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25130107) by changing a digit.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 534658 + ... + 534704.
Almost surely, 225130007 is an apocalyptic number.
25130007 is a gapful number since it is divisible by the number (27) formed by its first and last digit.
25130007 is a deficient number, since it is larger than the sum of its proper divisors (21705705).
25130007 is a wasteful number, since it uses less digits than its factorization.
25130007 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 130 (or 121 counting only the distinct ones).
The product of its (nonzero) digits is 210, while the sum is 18.
The square root of 25130007 is about 5012.9838419847. The cubic root of 25130007 is about 292.9077547835.
Adding to 25130007 its reverse (70003152), we get a palindrome (95133159).
The spelling of 25130007 in words is "twenty-five million, one hundred thirty thousand, seven".
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