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256893120000 = 293454111753
BaseRepresentation
bin1110111101000000000…
…1011110111000000000
3220120002022201122010000
43233100001132320000
513202104114320000
6314003131040000
724363023330346
oct3572001367000
9816068648100
10256893120000
1199a47518340
1241954ba0000
131b2c01b291a
14c6100a9996
156a38070000
hex3bd005ee00

256893120000 has 2000 divisors, whose sum is σ = 1127611636272. Its totient is φ = 57507840000.

The previous prime is 256893119971. The next prime is 256893120023. The reversal of 256893120000 is 21398652.

256893120000 is a `hidden beast` number, since 2 + 568 + 93 + 1 + 2 + 0 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (2000).

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 199 ways as a sum of consecutive naturals, for example, 4847039974 + ... + 4847040026.

Almost surely, 2256893120000 is an apocalyptic number.

256893120000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 256893120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (563805818136).

256893120000 is an abundant number, since it is smaller than the sum of its proper divisors (870718516272).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

256893120000 is an equidigital number, since it uses as much as digits as its factorization.

256893120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131 (or 91 counting only the distinct ones).

The product of its (nonzero) digits is 25920, while the sum is 36.

The spelling of 256893120000 in words is "two hundred fifty-six billion, eight hundred ninety-three million, one hundred twenty thousand".