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26140201135 = 55228040227
BaseRepresentation
bin11000010110000100…
…111101000010101111
32111110202101210201121
4120112010331002233
5412013342414020
620001511121411
71613531020636
oct302604750257
974422353647
1026140201135
11100a450a014
125096373267
132607821449
14139d98c51d
15a2ed49baa
hex61613d0af

26140201135 has 4 divisors (see below), whose sum is σ = 31368241368. Its totient is φ = 20912160904.

The previous prime is 26140201133. The next prime is 26140201169. The reversal of 26140201135 is 53110204162.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53110204162 = 226555102081.

It is a cyclic number.

It is not a de Polignac number, because 26140201135 - 21 = 26140201133 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (26140201133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2614020109 + ... + 2614020118.

It is an arithmetic number, because the mean of its divisors is an integer number (7842060342).

Almost surely, 226140201135 is an apocalyptic number.

26140201135 is a deficient number, since it is larger than the sum of its proper divisors (5228040233).

26140201135 is an equidigital number, since it uses as much as digits as its factorization.

26140201135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5228040232.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 26140201135 its reverse (53110204162), we get a palindrome (79250405297).

The spelling of 26140201135 in words is "twenty-six billion, one hundred forty million, two hundred one thousand, one hundred thirty-five".

Divisors: 1 5 5228040227 26140201135