Base | Representation |
---|---|
bin | 101101000111100000000… |
… | …001110110011110000111 |
3 | 101222101202022000222121212 |
4 | 231013200001312132013 |
5 | 401244140040031210 |
6 | 10332152355002035 |
7 | 436666355121641 |
oct | 55074001663607 |
9 | 11871668028555 |
10 | 3100430002055 |
11 | a959809a9781 |
12 | 420a7389931b |
13 | 1964a5456b19 |
14 | aa0c10cb891 |
15 | 559b15bb805 |
hex | 2d1e0076787 |
3100430002055 has 24 divisors (see below), whose sum is σ = 3955461729120. Its totient is φ = 2332540613120.
The previous prime is 3100430002027. The next prime is 3100430002093. The reversal of 3100430002055 is 5502000340013.
It is not a de Polignac number, because 3100430002055 - 238 = 2825552095111 is a prime.
It is a super-2 number, since 2×31004300020552 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 3100430002055.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 902990 + ... + 2648820.
It is an arithmetic number, because the mean of its divisors is an integer number (164810905380).
Almost surely, 23100430002055 is an apocalyptic number.
3100430002055 is a deficient number, since it is larger than the sum of its proper divisors (855031727065).
3100430002055 is a wasteful number, since it uses less digits than its factorization.
3100430002055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1747099 (or 1747082 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 23.
Adding to 3100430002055 its reverse (5502000340013), we get a palindrome (8602430342068).
The spelling of 3100430002055 in words is "three trillion, one hundred billion, four hundred thirty million, two thousand, fifty-five".
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