31101121319 has 2 divisors, whose sum is σ = 31101121320. Its totient is φ = 31101121318.

The previous prime is 31101121309. The next prime is 31101121321. The reversal of 31101121319 is 91312110113.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31101121319 - 2⁸ = 31101121063 is a prime.

It is a super-2 number, since 2×31101121319² (a number of 22 digits) contains 22 as substring.

Together with 31101121321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 31101121294 and 31101121303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31101121309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15550560659 + 15550560660.

It is an arithmetic number, because the mean of its divisors is an integer number (15550560660).

Almost surely, 2^31101121319 is an apocalyptic number.

31101121319 is a deficient number, since it is larger than the sum of its proper divisors (1).

31101121319 is an equidigital number, since it uses as much as digits as its factorization.

31101121319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 23.

The spelling of 31101121319 in words is "thirty-one billion, one hundred one million, one hundred twenty-one thousand, three hundred nineteen".